关于PHP将两个二维数组合并的问题

例如，我们现在有两个二维数组：

第一个二维数组：$first = array("0"=>array("a"=>"1","b"=>2,"c"=>"3"),"1"=>array("a"=>"4","b"=>5,"c"=>"6"),"2"=>array("a"=>"7","b"=>8,"c"=>"9"))

第二个二维数组：$second = array("0"=>array("d"=>"1","e"=>2,"f"=>"3"),"1"=>array("d"=>"4","e"=>5,"f"=>"6"),"2"=>array("d"=>"7","e"=>8,"f"=>"9"))

通过array_merge函数，我们可以合并两个二维数组合并为一个，一维数组的键从0-5;

我们希望实现合并后的数组一维数组的键不会增加，原两个数组相同键的数据会合并，实现方法如：

$count = count($first); //获取数组的数量

下面是重点：通过循环将原两个数组相同键的数据合并：

for($i=0;$i<$count;$i++){
$all[$i] = array_merge($first[$i],$second[$i]);
}

我们会发现，var_dump($all)后，会发现新的二维数组结构如下：$all = array(

"0"=>array("a"=>"1","b"=>2,"c"=>"3","d"=>"1","e"=>2,"f"=>"3"),

"1"=>array("a"=>"4","b"=>5,"c"=>"6","d"=>"4","e"=>"5","f"=>"6"),

"2"=>array("a"=>"7","b"=>8,"c"=>"9","d"=>"7","e"=>"8","f"=>"9")

)