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c# webapi POST 参数解决方法

创建时间:2015-10-21 投稿人: 浏览次数:22375

HttpWebRequest POST请求webapi:如果参数是简单类型,比如字符串(注意,拼接的字符串要HttpUtility.UrlEncode才行,否则服务端会丢失特殊字符&后面的数据)

要点:如下代码统一设置为:ContentType = "application/x-www-form-urlencoded";

服务端代码1:URL格式为 POSTapi/Values

public string Post([FromBody] string value)

则客户端Post的数据:拼接的字符串必须以 =开头,否则服务端无法取得value。例如:=rfwreewr2332322232 或者 {"":value}

服务端代码2:URL格式为 POST api/Values?value={value}

public string Post(string value)

则客户端Post的数据:需要url里拼接出KeyValue这样的数据

服务端代码3:URL格式为 POST api/Values

public string Post()

则客户端Post的数据:无要求。例如:key=rfwreewr2332322232。

服务端:可以用HttpContext.Current.Request.InputStream或者HttpContext.Current.Request.Form[0]都可以获取


如果post的参数类型比较复杂,则需要自定义类

要点:如下代码统一设置为:ContentType = "application/json";

服务端代码1:URL格式为 POST api/Values

public string Post([FromBody] Model value)或者 public string Post(Model value)

则客户端Post的数据:{"id":"test1","name":"value"}。服务端会自动映射到对象。

提交代码如下:

            HttpWebRequest wReq = (HttpWebRequest)WebRequest.Create("http://localhost:37831/api/Values");
            wReq.Method = "Post";
            //wReq.ContentType = "application/json";
            //wReq.ContentType = "application/x-www-form-urlencoded";
            wReq.ContentType = "application/json";

            //byte[] data = Encoding.Default.GetBytes(HttpUtility.UrlEncode("key=rfwreewr2332322232&261=3&261=4"));
            byte[] data = Encoding.Default.GetBytes("{"id":"test1","name":"value"}");
            wReq.ContentLength = data.Length;
            Stream reqStream = wReq.GetRequestStream();
            reqStream.Write(data, 0, data.Length);
            reqStream.Close();
            using (StreamReader sr = new StreamReader(wReq.GetResponse().GetResponseStream()))
            {
                string result = sr.ReadToEnd();

               
            }
服务段代码如下:

        // POST api/values
        //public string Post()
        //{
        //    FileInfo fi = new FileInfo(AppDomain.CurrentDomain.BaseDirectory + "log.txt");
        //    StreamWriter sw = fi.CreateText();
        //    StreamReader sr = new StreamReader(HttpContext.Current.Request.InputStream);
        //    sw.WriteLine("1:" + sr.ReadToEnd()+"--"+ HttpContext.Current.Request.Form[0]);
        //    sw.Flush();
        //    sw.Close();
        //    return "{"test":"1"}";
        //}

        // POST api/values
        public HttpResponseMessage PostStudent(Student student)
        {
            FileInfo fi = new FileInfo(AppDomain.CurrentDomain.BaseDirectory + "log.txt");
            StreamWriter sw = fi.AppendText();

            sw.WriteLine("2:" + student.id);
            sw.Flush();
            sw.Close();
            HttpResponseMessage result = new HttpResponseMessage { Content = new StringContent("{"test":"2"}", Encoding.GetEncoding("UTF-8"), "application/json") };
            return result;
        }


这篇文章里有的方法也不错:http://www.cnblogs.com/rohelm/p/3207430.html



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