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android对list对象中的string字符串进行排序

创建时间:2016-03-31 投稿人: 浏览次数:2308

废话不多说,直接上代码,亲测
public class Person {

    public int age;
    public String beginTime;
    public String name;

    public Person(int age, String beginTime, String name) {
        super();
        this.age = age;
        this.beginTime = beginTime;
        this.name = name;
    }

    public Person() {
        super();
    }

}


public class HahaTime2 {

    public static void main(String[] args) {
        /**
         * 原来的日期
         */
        List<Person> list = new ArrayList<Person>();
        list.add(new Person(1,"2016-04-22 15:30:28", "小芳"));
        list.add(new Person(1,"2016-03-02 15:30:28", "小花"));
        list.add(new Person(1,"2016-02-12 15:30:28", "小狗"));
        list.add(new Person(1,"2016-12-02 15:30:28", "小猫"));
        list.add(new Person(1,"2016-02-02 15:30:28", "小米"));
        list.add(new Person(1,"2016-02-12 15:30:28", "小明"));
        
        Collections.sort(list, new MapComparator());
        for (Person person : list) {
            System.out.println(person.name+";"+person.beginTime);
        }
    }

}
class MapComparator implements Comparator<Person>{

    public int compare(Person lhs, Person rhs) {
        return lhs.beginTime.compareTo(rhs.beginTime);
    }

}

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