判断数组对象中是否包含某个对象,判断2个对象是否相等
var arr =[
{name:"zhangsan"},
{name:"lisi"},
{name:"wangwu"}
];
var json1 = {name:"zhangsan"};
// 方法一:(兼容ie8)
console.log(JSON.stringify(arr).indexOf(JSON.stringify(json1)));
// 方法二: (前提是匹配和被匹配的存在赋值关系)
var json2 = arr[0];
var json3 = {name:"zhangsan"};
console.log("json2",arr.indexOf(json2)); // 存在
console.log("json3",arr.indexOf(json3)); //不存在
underscore 中isEqual的源码;
// Internal recursive comparison function for `isEqual`.
var eq = function(a, b, aStack, bStack) {
// Identical objects are equal. `0 === -0`, but they aren"t identical.
// See the [Harmony `egal` proposal](http://wiki.ecmascript.org/doku.php?id=harmony:egal).
if (a === b) return a !== 0 || 1 / a === 1 / b;
// A strict comparison is necessary because `null == undefined`.
if (a == null || b == null) return a === b;
// Unwrap any wrapped objects.
if (a instanceof _) a = a._wrapped;
if (b instanceof _) b = b._wrapped;
// Compare `[[Class]]` names.
var className = toString.call(a);
if (className !== toString.call(b)) return false;
switch (className) {
// Strings, numbers, regular expressions, dates, and booleans are compared by value.
case "[object RegExp]":
// RegExps are coerced to strings for comparison (Note: "" + /a/i === "/a/i")
case "[object String]":
// Primitives and their corresponding object wrappers are equivalent; thus, `"5"` is
// equivalent to `new String("5")`.
return "" + a === "" + b;
case "[object Number]":
// `NaN`s are equivalent, but non-reflexive.
// Object(NaN) is equivalent to NaN
if (+a !== +a) return +b !== +b;
// An `egal` comparison is performed for other numeric values.
return +a === 0 ? 1 / +a === 1 / b : +a === +b;
case "[object Date]":
case "[object Boolean]":
// Coerce dates and booleans to numeric primitive values. Dates are compared by their
// millisecond representations. Note that invalid dates with millisecond representations
// of `NaN` are not equivalent.
return +a === +b;
}
if (typeof a != "object" || typeof b != "object") return false;
// Assume equality for cyclic structures. The algorithm for detecting cyclic
// structures is adapted from ES 5.1 section 15.12.3, abstract operation `JO`.
var length = aStack.length;
while (length--) {
// Linear search. Performance is inversely proportional to the number of
// unique nested structures.
if (aStack[length] === a) return bStack[length] === b;
}
// Objects with different constructors are not equivalent, but `Object`s
// from different frames are.
var aCtor = a.constructor, bCtor = b.constructor;
if (
aCtor !== bCtor &&
// Handle Object.create(x) cases
"constructor" in a && "constructor" in b &&
!(_.isFunction(aCtor) && aCtor instanceof aCtor &&
_.isFunction(bCtor) && bCtor instanceof bCtor)
) {
return false;
}
// Add the first object to the stack of traversed objects.
aStack.push(a);
bStack.push(b);
var size, result;
// Recursively compare objects and arrays.
if (className === "[object Array]") {
// Compare array lengths to determine if a deep comparison is necessary.
size = a.length;
result = size === b.length;
if (result) {
// Deep compare the contents, ignoring non-numeric properties.
while (size--) {
if (!(result = eq(a[size], b[size], aStack, bStack))) break;
}
}
} else {
// Deep compare objects.
var keys = _.keys(a), key;
size = keys.length;
// Ensure that both objects contain the same number of properties before comparing deep equality.
result = _.keys(b).length === size;
if (result) {
while (size--) {
// Deep compare each member
key = keys[size];
if (!(result = _.has(b, key) && eq(a[key], b[key], aStack, bStack))) break;
}
}
}
// Remove the first object from the stack of traversed objects.
aStack.pop();
bStack.pop();
return result;
};
// Perform a deep comparison to check if two objects are equal.
_.isEqual = function(a, b) {
return eq(a, b, [], []);
};声明:该文观点仅代表作者本人,入门客AI创业平台信息发布平台仅提供信息存储空间服务,如有疑问请联系rumenke@qq.com。
- 上一篇: js中arr的赋值不影响原数组,赋值和引用的区别
- 下一篇: 防止表单重复提交的方法
