数组a,数组b，复制到数组c

<span style="font-size:18px;">package lianx1;


import java.util.Arrays;


public class ArrayTest2 {
	/*
	 *.现在给出两个数组：    数组A：{1,7,9,11,13,15,17,19}；  
	 * · 数组b：{2,4,6,8,10}   两个数组合并为数组c,按升序排列。
	 */
	public static void main(String[] args) {
		int a[] = { 1, 7, 9, 11, 13, 15, 17, 19 };
		int b[] = { 2, 4, 6, 8, 10 };
		int c[] = new int[a.length + b.length];
		copyArray(a, b, c);
		copyArray1(a, b, c);
		// System.arraycopy(a, 0, c, 0, a.length);
		// System.arraycopy(b, 0, c, a.length, b.length);


	}
/*
 * 通过原生封装好的方法，实现
 */
	private static void copyArray1(int[] a, int[] b, int[] c) {
		System.arraycopy(a, 0, c, 0, a.length);
		System.arraycopy(b, 0, c, a.length, b.length);
		Arrays.sort(c);
		System.out.println(Arrays.toString(c));


	}
	/*
	 * 解法一，通过遍历数组，将数据保存到新的数组
	 */
	private static void copyArray(int[] a, int[] b, int[] c) {
		int index = 0;
		for (int i = 0; i < a.length; i++) {
			c[index++] = a[i];
		}
		System.out.println(index);// 8
		for (int i = 0; i < b.length; i++) {
			c[index++] = b[i];
		}
		Arrays.sort(c);
		System.out.println(Arrays.toString(c));


	}


}</span>